The electric field strength is 10kN / C. What is the strength of the electric field acting on the 2μCL charge?

Task data: E (value of the electric field strength) = 10 kN / Kl (10 * 10 ^ 3 N / Kl); q (charge value) = 2 μC (2 * 10 ^ -6 C).

The force with which the electric field will act on the charge under consideration will be equal to the product of the electric field strength and the magnitude of this charge: F = q * E.

Calculation: F = 2 * 10 ^ -6 * 10 * 10 ^ 3 = 0.02 N.

Answer: An electric field acts on a charge with a force of 0.02 N.



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