The electric forklift lifts a 500kg load to a height of 2m. The engine is powered by a 24V

The electric forklift lifts a 500kg load to a height of 2m. The engine is powered by a 24V battery at 41A and 80% efficiency. Determine the speed of lifting the load under these conditions.

Let’s find the engine power that it develops when lifting

Pd = U * I = 24 * 41 = 984 W.

Some of this power is lost to heating and friction, the efficiency is 80%. Find the useful power

P = Pd * efficiency / 100% = 984 * 80% / 100% = 787.2 W.

Let’s translate the mass of the load, kilogram, into force in newtons

F = 500 * 9.8 = 4900 N.

The formula for the dependence of power on strength and speed:

P = F * V.

Then

V = P / F.

Substitute the known quantities

V = 787.2 / 4900 = 0.16 m / s.

Answer: the speed of lifting the load is 0.16 m / s.