The electric iron has a power of 150 kW. The voltage in the circuit is 220V. Specify: a) Iron resistance;
| December 29, 2020 | education
The electric iron has a power of 150 kW. The voltage in the circuit is 220V. Specify: a) Iron resistance; b) Work done with electric current in 15 minutes.
Power of ANY electrical element – P = UI = U ^ 2 / R
For question (a), from this equation, we obtain that the iron resistance R = U ^ 2 / P = 220 * 220 / 150,000 Ohm
work A is equal to:
A = P * t = 150,000 * 60 * 15 J
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