The electric iron is designed for a voltage of 200 V. The resistance of its heating element is 88 ohms.
| March 5, 2021 | education
The electric iron is designed for a voltage of 200 V. The resistance of its heating element is 88 ohms. Determine the energy consumed by the iron in 30 minutes.
U = 200 V.
R = 88 ohms.
t = 30 min = 1800 s.
Q -?
N -?
The amount of thermal energy Q, which is released in a conductor with a current, is determined by the formula of the Joule-Lenz law: Q = U2 * t / R, where U is the voltage, t is the operating time of the iron, R is the resistance of the iron.
Q = (200 V) 2 * 1800 s / 88 Ohm = 818181.8 J.
Power N is the ratio of the energy consumed by the iron Q to the time of its consumption t: N = Q / t.
N = 818181.8 J / 1800 s = 454.5 W.
Answer: the iron has a power of N = 454.5 W and consumes electricity Q = 818181.8 J.
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