The electric locomotive moves at a constant speed of 46.8 km / h, developing at this speed a traction force of 216 kN.
The electric locomotive moves at a constant speed of 46.8 km / h, developing at this speed a traction force of 216 kN. The efficiency of the electric locomotive engine is 78%. What is the current in the motor winding if the mains voltage is 3000 V?
To solve the problem, let’s translate km / h into m / s, and kN into N.
V = 46.8 km / h = 46800 m / 3600 s = 13 m / s;
F = 216 kN = 216000 N.
Let’s calculate the power that is needed to maintain movement
N = V * F = 13 * 216000 = 2808000 W.
Let’s find the power of the electric locomotive when doing this work
Efficiency = 78% / 100% = 0.78;
Ne = N / efficiency = 2808000 W / 0.78 = 3600000 W.
Find the current in the motor
I = Ne / U = 3600000 W / 300 V = 12000 A.
Answer: the current in the motor winding is 12000 A.