The electric locomotive moves at a constant speed of 46.8 km / h. The current consumed by the electric locomotive

The electric locomotive moves at a constant speed of 46.8 km / h. The current consumed by the electric locomotive from the network with a voltage of 3000 V is 1200 A. The efficiency of the electric locomotive engine is 78%. What is the traction force of an electric locomotive engine?

Given:

v = 46.8 km / h (translated into SI) = (46.8 * 1000) / 3600 = 13 m / s;

1000 – meters per kilometer, 3600 – seconds per hour;

U = 3000 B;

I = 1200 A;

Efficiency = 78% = n = 0.78;

To find:

Ftyag -?

Decision:

From the formula: n = Ap / Az = (Ftyag * V) / (I * U) we express the engine thrust force:

Ftyag = (n * U * I) / V = (0.78 * 3000 * 1200) / 13 = 216500 H;

Answer: 216500 H.