The electric locomotive on the horizontal section of the track develops a thrust of 200kH.

The electric locomotive on the horizontal section of the track develops a thrust of 200kH. the composition of what mass it can carry with an acceleration of 0.1 m / s, if the force of resistance of movement is 30kN.

Ftag = 200 kN = 200000 N.

Fcopr = 30 kN = 30,000 N.

a = 0.1 m / s2.

m -?

According to Newton’s 2 law, the mass of a body m can be found by dividing the value of the resultant of all forces Fр by the acceleration of the body a: m = Fр / a.

The resultant of all forces Fr is the vector sum of all forces that act on the body: Fr = Ftag + Fcopr.

Since the resistance force Fcopr is always directed in the opposite direction of the movement of the electric locomotive, and therefore in the opposite direction to the traction force Ftyag, the resultant will be the difference: Fr = Ftyag – Fcopr.

m = (Ftyag – Fcopr) / a.

m = (200,000 N – 30,000 N) / 0.1 m / s2 = 1,700,000 kg.

Answer: the mass of a train that an electric locomotive can carry is m = 1,700,000 kg.