The electric locomotive operates at a voltage of 3 kV, develops a speed of 12 m / s

| February 13, 2021 | education

The electric locomotive operates at a voltage of 3 kV, develops a speed of 12 m / s and a traction force of 340 kN. Motor efficiency 85%, what is the current in the motor winding?

U = 3 kV = 3000 V.

V = 12 m / s.

F = 340 kN = 340000 N.

Efficiency = 85%.

I -?

Efficiency = Ap * 100% / Az, where Ap – useful work, Az – expended work.

We express the useful work An by the formula: An = F * S, where F is the traction force of the train, S is the movement of the train.

The spent work Az will be expressed by the formula: Az = I * U * t, where I is the current in the electric locomotive engine, U is the current voltage, t is the operating time of the electric locomotive.

Efficiency = F * S * 100% / I * U * t.

With uniform rectilinear motion, the ratio of the distance traveled S to the time it passes t is called the speed of movement V: V = S / t.

Efficiency = F * V * 100% / I * U.

We find the current strength in the winding I of the motor by the formula: I = F * V * 100% / efficiency * U.

I = 340,000 N * 12 m / s * 100% / 85% * 3000 V = 1600 A.

Answer: the current in the motor is I = 1600 A.



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