The electric locomotive with a thrust force of 350 kN develops a power of 4100 kW.

The electric locomotive with a thrust force of 350 kN develops a power of 4100 kW. How long does an electric locomotive travel 33 km?

Initial data: F (traction force of the electric locomotive) = 350 kN (350 * 10 ^ 3 N); N (the power that the electric locomotive develops) = 4100 kW (4100 * 10 ^ 3 W); S (the path that the electric locomotive must travel) = 33 km (33 * 10 ^ 3 m).

1) Determine the speed of the electric locomotive: N = F * V, whence V = N / F = 4100 * 10 ^ 3 / (350 * 10 ^ 3) = 11.714 m / s.

2) The time during which the electric locomotive will pass the given path: t = S / V = 33 * 10 ^ 3 / 11.714 ≈ 2817 s ≈ 47 minutes.

Answer: The electric locomotive will cover the given distance in 47 minutes.



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