The electric locomotive with a thrust force of 350 kN develops a power

The electric locomotive with a thrust force of 350 kN develops a power of 4100 kW. How long does it take for an electric locomotive to travel 33 km?

As we know from the school physics curriculum, the power can be calculated using the following formula:

N = A / t, where A is the work performed for a period of time equal to t.

Let us determine what work will be done when it is known that the traction force of the electric locomotive is 350 kN, and the path to be overcome is 33 km:

A = F * S;

350 kN = 1000 * 350 = 350,000 N;

33 km = 1000 * 33 = 33000 m;

350000 * 33000 = 11550000000.

Let’s define the time:

4100 kW = 4100000 W;

11550000000: 4100000 ≈ 2817 s.

Answer: 2817 p.