The electric motor of the crane operates under a voltage of 380 V. What amperage passes through it

The electric motor of the crane operates under a voltage of 380 V. What amperage passes through it, if the efficiency of the installation is 50%, and the crane lifts a load of 1 ton to a height of 20 m in 50 s

To find out the current in the electric motor of the specified crane, we will use the formula: η = Apol / Azatr = ΔEp / (U * I * t) = m * g * Δh / (U * I * t), from where we express: I = m * g * Δh / (η * U * t).

Const: q – acceleration due to gravity (q ≈ 9.81 m / s2).

Data: m is the mass of the cargo (m = 1 t, in the SI system m = 103 kg); Δh – change in the height of the cargo (Δh = 20 m); η – crane efficiency (η = 50% = 0.5); U – operating voltage (U = 380 V); t – elapsed time (t = 50 s).

Let’s perform the calculation: I = m * g * Δh / (η * U * t) = 10 ^ 3 * 9.81 * 20 / (0.5 * 380 * 50) = 20.65 A.

Answer: The current in the electric motor should be equal to 20.65 A.



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