The electric train leaving the station for 0.5 min moved with an acceleration of 0.8

The electric train leaving the station for 0.5 min moved with an acceleration of 0.8 m / sec2, determine the path that it traveled during this time

Task data: V0 (initial speed) = 0 m / s (the electric train departed from the station); t (duration of movement) = 0.5 min (30 s); a (acceleration with which the electric train was moving) = 0.8 m / s2.

The path that the electric train has traveled is determined by the formula: S = V0 * t + 0.5 * a * t ^ 2 = 0 + 0.5 * a * t ^ 2 = 0.5 * a * t ^ 2.

Calculation: S = 0.5 * 0.8 * 30 ^ 2 = 360 m.

Answer: The electric train covered 360 meters in half a minute.