The electric train leaving the station moved with an acceleration of 0.8 m / s² for 0.5 min.

The electric train leaving the station moved with an acceleration of 0.8 m / s² for 0.5 min. Determine the path that he traveled during this time, and the speed at the end of the path.

V0 = 0 m / s.

t = 0.5 min = 30 s.

a = 0.8 m / s ^ 2.

V -?

S -?

Let us write the formulas for determining the acceleration a and the distance traveled S for uniformly accelerated motion: a = (V – V0) / t, S = V0 * t + a * t ^ 2/2, where V, V0 are the final and initial speed of movement, t – movement time.

Since the train moves from a state of rest, then V0 = 0 m / s.

The formulas will take the form: a = V / t, S = a * t ^ 2/2.

Let us express the final speed: V = a * t.

V = 0.8 m / s ^ 2 * 30 s = 24 m / s.

S = 0.8 m / s ^ 2 * (30 s) ^ 2/2 = 360 m.

Answer: the speed of the train will become V = 24 m / s, it will cover the path S = 360 m.