The electron begins to move from one point of the electric field to another. What speed will the electron

The electron begins to move from one point of the electric field to another. What speed will the electron acquire if the voltage between these points is U = 4.1V? electron mass m0 = 9.1 * 10 ^ -31.

q = 1.6 * 10 ^ -19 Cl.

U = 4.1V.

m = 9.1 * 10 ^ -31 kg.

V -?

The work of the electrostatic field A on the movement of the charge is determined by the formula: A = q * U, where q is the magnitude of the electric charge, U is the voltage between the initial and final position of the charge.

Work A is equal to the change in the kinetic energy of the body ΔEk = Ek – Ek0.

The kinetic energy Ek is determined by the formula: Ek = m * V ^ 2/2, where m is the mass of the body, V is the speed of movement of the body.

Since V0 = 0 m / s, the electron begins to move from a state of rest, then ΔEk = m * V ^ 2/2.

q * U = m * V ^ 2/2.

V = √ (2 * q * U / m).

V = √ (2 * 1.6 * 10 ^ -19 C * 4.1 V / 9.1 * 10 ^ -31 kg = 397000 m / s.

Answer: the electron will acquire a speed V = 397000 m / s.