The elevator rises with an acceleration of 1.5 m / s. If the body weight is 10 kg

The elevator rises with an acceleration of 1.5 m / s. If the body weight is 10 kg, then its weight is in the elevator.

m = 10 kg.

g = 9.8 m / s2.

a = 1.5 m / s2.

R – ?

The weight of the body P is the force with which the body presses on the support or stretches the suspension.

Two forces act on the body in the elevator: the force of gravity Ft directed vertically downward, the force N of the pressure of the floor of the elevator on the body directed vertically upward.

m * a = m * g + N – 2 Newton’s law in vector form.

For projections onto the vertical axis 2, Newton’s law will take the form: m * a = – Fт + N.

N = m * a + Fт.

The force of gravity Ft is determined by the formula: Ft = m * g.

N = m * a + m * g = m * (a + g).

According to Newton’s 3 law, P = – N, the sign “-” indicates the opposite direction of forces.

P = m * (a + g).

P = 10 kg * (9.8 m / s2 + 1.5 m / s2) = 147 N.

Answer: when the lift moves, the body weight is P = 147 N.