The EMF of the battery is 26 Volts. when it is closed to the load, the voltage at the poles of the battery

The EMF of the battery is 26 Volts. when it is closed to the load, the voltage at the poles of the battery becomes equal to 24 volts. What is the load impedance if the internal impedance of the source is 1 ohm.

Find the voltage drop of the battery when the load is connected

Uп = U1 – U2 = 26 – 24 = 2 B.

This drop occurred at the internal resistance of the current source. Determine the circuit current

I = Uп / Rв = 2/1 = 2 A.

Calculate the load resistance

Rн = U2 / I = 24/2 = 12 ohms.

Answer: load resistance 12 ohms.



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