The EMF of the battery is 6V, and the internal resistance is 0.06 Ohm, which will be shown by a

The EMF of the battery is 6V, and the internal resistance is 0.06 Ohm, which will be shown by a voltmeter connected to the battery terminals, which is closed to a 54W consumer.

To solve this problem, you first need to determine the value of the current in this circuit.

To do this, we divide the voltage value by the resistance.

In this case, we get:

6 / 0.06 = 100 Amperes.

In order to determine the voltage value on the voltmeter, it is necessary to divide the known power of the consumer by the received current in the circuit.

In this case, the voltage on the voltmeter will show:

54/100 = 0.54 V.

Answer:

The voltmeter will show 0.54 V.