The EMF of the current source is 8 V. A conductor with a resistance of 30 ohms was connected to the poles of this source.

The EMF of the current source is 8 V. A conductor with a resistance of 30 ohms was connected to the poles of this source. The voltage between the ends of the conductor is 6 V. What is the internal resistance of such a body source?

In this problem, from Ohm’s law for a complete circuit, the formula for the internal resistance is found as r = E-U / I, starting with I = 6/30 = 0.2 A, and hence r = 8-6 / 0.2 = 10 Ohm.



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