The end of the clock hand, which is 1 cm long, has moved from 12 o’clock to 6 o’clock.

The end of the clock hand, which is 1 cm long, has moved from 12 o’clock to 6 o’clock. In this case, the path and modulus of movement of the arrow end are respectively equal.

Given:

x1 = 12 o’clock – the initial position of the hand;

x2 = 6 o’clock – end position of the hand;

r = 1 centimeter = 0.01 meter – arrow radius;

pi = 3.14 is a geometric constant.

It is required to determine the path S traversed by the arrow and the displacement modulus L.

According to the condition of the problem, the hand has moved from 12 o’clock to 6 o’clock, that is, it has passed half the circumference of the dial. Then:

S = C / 2, where C is the circumference that the clock hand describes.

S = 2 * pi * r / 2 = pi * r = 3.14 * 0.01 = 0.0314 meters = 3.14 centimeters.

The modulus of movement of the arrow will be equal to:

L = 2 * r = 2 * 0.01 = 0.02 meters = 2 centimeters.

Answer: the distance traveled is 3.14 centimeters, the modulus of movement is 2 centimeters