The energy consumption in an electric lamp at a current strength of 0.5A, during 8 hours is 1728 kJ.

The energy consumption in an electric lamp at a current strength of 0.5A, during 8 hours is 1728 kJ. What is the resistance of the lamp?

Task data: I (current in a given electric lamp) = 0.5 A; t (lamp operating time) = 8 hours (in SI t = 28800 s); Q (consumed energy) = 1728 kJ (1728 * 10 ^ 3 J).

We express the resistance of a given electric lamp from the formula: Q = I2 * R * t, whence R = Q / (I2 * t).

Let’s calculate: R = 1728 * 10 ^ 3 / (0.52 * 28800) = 240 Ohm.

Answer: A given electric lamp has a resistance of 240 ohms.



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