The energy of the flash lamp powered by the capacitor is 36 J. The capacitance of the capacitor is 800 μF.
| August 7, 2021 | education
The energy of the flash lamp powered by the capacitor is 36 J. The capacitance of the capacitor is 800 μF. Calculate the voltage to which the capacitor is charged.
Initial data: E (lamp flash energy) = 36 J; C (electrical capacity of the capacitor from which the lamp is powered) = 800 μF (800 * 10-6 F).
The voltage to which the capacitor was charged is calculated from the formula: E = 0.5 * C * U2, whence U2 = 2E / C and U = √ (2E / C).
Let’s make the calculation: U = √ (2 * 36 / (800 * 10-6)) = √90000 = 300 V.
Answer: The capacitor was charged to a voltage of 300 V.
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