The engine did a useful job equal to 115 MJ, and at the same time consumed 9 kg of gasoline
| May 1, 2021 | education
The engine did a useful job equal to 115 MJ, and at the same time consumed 9 kg of gasoline. Calculate the efficiency of this motor.
These tasks: Ap (useful work performed by the engine used) = 115 MJ (115 * 10 ^ 6 J); m (mass of consumed gasoline) = 9 kg.
Constants: qb (specific heat of combustion of gasoline) = 46 * 10 ^ 6 J / kg.
The efficiency of the motor used can be calculated by the formula: η = Ap / Az = Ap / (qb * m).
Calculation: η = 115 * 10 ^ 6 / (46 * 10 ^ 6 * 9) ≈ 0.278 or 27.8%.
Answer: The motor used has an efficiency of 27.8%.
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