The engine performed 149.6 MJ in a time of 2.2 hours. Find the power of this motor in kW
| March 1, 2021 | education
These tasks: t (the duration of the engine taken) = 2.2 h (in Cu t = 2.2 * 3600 s = 7920 s); A (useful work of the engine for a given period of time) = 149.6 MJ (149.6 * 10 ^ 6 J).
The power of the engine taken can be calculated using the formula: N = A / t.
Calculation: N = 149.6 * 10 ^ 6/7920 = 18 889 W ≈ 18.9 kW.
Answer: The power of the engine taken is 18.9 kW.
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