The engine receives 0.5 MJ of heat from heating. Engine efficiency 35%. How much heat is transferred to the refrigerator?
| January 4, 2021 | education
Given:
Qн = 0.5 MJ = 500000 J
n = 35% n = 0.35
Find: Qx =?
Decision:
n = 1- (Qx / Qn)
1-n = Qx / Qн
Qx = Qн * (1-n)
Qx = 500000J * (1-0.35)
Qx = 325000 J
Answer: Qx = 325000 J.
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