The equation of motion has the following form X (t) = 3 + 6t-0.5t ^ 2 how long will the body stop after the start of motion?
| March 20, 2021 | education
These tasks: the equation of motion of the conditional body: X (t) = 3 + 6t – 0.5t ^ 2; V (required body speed) = 0 m / s.
The equation of speed change: V (t) = x (t) ‘= (3 + 6t – 0.5t ^ 2)’ = 0 + 6 * 1 – 0.5 * 2 * t = 6 – t.
Duration of movement to stop: V (t) = 0 = 6 – t, whence t = 6 s.
Answer: The stop of the conditional body will occur 6 seconds after the start of its movement.
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