The equation of motion of a material point has the form x = A + Bt + CR^2, where A = 6 m, B = 4 m, C = 1 m / s2.

| June 11, 2021 | education

The equation of motion of a material point has the form x = A + Bt + CR^2, where A = 6 m, B = 4 m, C = 1 m / s2. Determine the modulus of the speed of movement of the point after the time interval delta t = 7s after the start of the timing

x (t) = A + B * t + C * t ^ 2.

A = 6 m.

B = 4 m / s.

C = 1 m / s2.

t = 7 s.

V -?

With uniformly accelerated motion, the dependence of the coordinate of the body on time х (t) has the form: х (t) = х0 + V0 * t + a * t ^ 2/2, where х0 is the initial coordinate of the body, V0 is the initial velocity of movement, a is the acceleration body.

For the dependence x (t) = A + B * t + C * t ^ 2, x0 = A = 6 m, V0 = B = 4 m / s, a = 2 * C = 2 m / s2.

With uniformly accelerated motion, the speed of the body V (t) changes according to the law: V (t) = V0 + a * t.

V = 4 m / s + 2 m / s2 * 7 s = 18 m / s.

Answer: the speed module was V = 18 m / s.



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