The equation of oscillation of a spring pendulum weighing 200 g has the form x = 0.05cos (8пt + п / 3).

The equation of oscillation of a spring pendulum weighing 200 g has the form x = 0.05cos (8пt + п / 3). Determine the stiffness of the spring if its mass can be neglected.

We need several formulas.
Let’s write the first one:
Ω = √ (k / m);

Now let’s write the equation of oscillations:
ω = 8π;

It remains only to square and equate:
k / m = 64 * π²;
Substitute the values into the formula and calculate:
k = 64 * π² * 0.200 ≈ 126 N / m;
Answer: k ≈ 126 N / m.