The equation of the coordinate of the point is x = 6-4t + t ^ 2, what is the modulus of its movement

The equation of the coordinate of the point is x = 6-4t + t ^ 2, what is the modulus of its movement during the first 5s of movement?

To determine the value of the modulus of movement of a given point, we will use the formula: x = x (t1) – x (t0).

Functions and variables: x (t) – the equation of motion of a point (x (t) = 6 – 4t + t ^ 2); t1 – considered moment of time (t1 = 5 s); t0 – initial moment (t0 = 0 s).

Calculation: x = x (t1) – x (t0) = (6 – 4 * 5 + 5 ^ 2) – (6 – 4 * 0 + 02) = 5 m.

Answer: In the first 5 s, the point movement module was 5 meters.