The escalator moves at a speed of 3 m / s modulo. At what speed and in what direction should a person
The escalator moves at a speed of 3 m / s modulo. At what speed and in what direction should a person move along the escalator in order to remain stationary relative to the ground? And at what speed relative to the ground will a person move if he walks along the escalator with the found speed in the direction of movement escalator?
Given:
v1 = 3 m / s – the speed of the escalator relative to the ground;
v2 = 0 m / s – the speed of a person on the escalator relative to the ground.
It is required to determine v – the speed of movement of a person relative to the escalator.
In order for a person to be motionless relative to the ground, the equality must be fulfilled:
v1 + v = 0
v = -v1 = – 3 m / s. A minus sign indicates that the direction of speed is opposite to that of the escalator.
If at this speed a person goes in the direction of the escalator, then his speed relative to the ground will be equal to:
v3 = v1 + v = 3 + 3 = 6 m / s.
Answer: to remain stationary relative to the ground, a person must move at a speed of 3 m / s in the direction opposite to the movement of the escalator.
