The evaporation of ammonia taken at the boiling point consumed 364 kJ of energy.
| September 7, 2021 | education
The evaporation of ammonia taken at the boiling point consumed 364 kJ of energy. Find the mass of the evaporated ammonia.
Task data: Q (consumed heat for evaporation of ammonia) = 364 kJ (364 * 10 ^ 3 J); ammonia was at boiling point.
Reference values: L (specific heat of vaporization) = 1.4 * 10 ^ 6 J / kg.
The mass of the evaporated ammonia can be calculated by the formula: m = Q / L.
Let’s calculate: m = 364 * 10 ^ 3 / (1.4 * 10 ^ 6) = 0.26 kg (260 g).
Answer: The mass of the evaporated ammonia is 260 grams.
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