The excavator bucket removes 750 kg of soil from a hole 0.5 m deep to the surface of the earth. What kind of work does it do?

m = 750 kg.

h = 0.5 m.

g = 10 N / kg.

A -?

We express the work of the excavator A when lifting the soil by the formula: A = F * S, where F is the force with which the excavator lifts the bucket with the soil, S is the movement of the soil.

We will assume that the lifting of the soil occurs vertically, evenly in a straight line, therefore, the force of lifting the bucket F should be equal to the gravity of the soil m * g: F = m * g.

The movement of the load S is equal to the height to which the soil is lifted, that is, the depth of the pit h: S = h.

A = m * g * h.

A = 750 kg * 10 N / kg * 0.5 m = 3750 J.

Answer: the excavator performs work A = 3750 J.