The field strength of a flat capacitor with a capacity of 10 μF is 20 kV / m, and the distance

The field strength of a flat capacitor with a capacity of 10 μF is 20 kV / m, and the distance between the plates is 1 cm. The field energy of the capacitor is …

Initial data: C (electrical capacity of the taken flat capacitor) = 10 μF (10 * 10 ^ -6 F); E (field strength of the capacitor) = 20 kV / m (20 * 10 ^ 3 V / m); d (distance between plates) = 1 cm (0.01 m).

The field energy of the taken flat capacitor is determined by the formula: W = 0.5 * C * U2 = 0.5 * C * (E * d) ^ 2.

Let’s make a calculation: W = 0.5 * 10 * 10 ^ -6 * (20 * 103 * 0.01) ^ 2 = 0.2 J.

Answer: The field energy of the taken flat capacitor is 0.2 J.