The figure shows a bar that moves under the action of two traction forces F equal to 1.85H and a resistance force Fc

The figure shows a bar that moves under the action of two traction forces F equal to 1.85H and a resistance force Fc equal to 1.3H. What is the mass of the bar if it moves with an acceleration of 0.5 m

According to Newton’s second law: the sum of all forces acting on a body is equal to the product of the mass of this body by its acceleration.
In vector form: Fthroat + F resistance = ma
m = (Ft + Fc) / a
The resistance force and the traction force are directed in opposite directions, therefore m = (Fт-Fc) / a = (1.85-1.3) / 0.5 = 1.1 kg.
Answer: m = 1.1 kg.