The first angle of the triangle is 40 degrees, and the second is 16 degrees greater than the third. Find the corners of this triangle.

By the theorem, the sum of all the angles of a triangle is 180 degrees.
180-40 = 140 degrees – angle 2 + angle 3
we denote the angle 2 for x, then the angle 3 = x + 16, make up the equation: x + 16 + x = 140,
2x = 124,
x = 62,
x + 16 = 62 + 16 = 78
Answer: angle 1 = 40 degrees, angle 2 = 62 degrees, angle 3 = 78 degrees