The first half of the journey the car moved uniformly at a speed of 22.2 m / s

The first half of the journey the car moved uniformly at a speed of 22.2 m / s, and the second half – unevenly with an average speed of 11.1 m / s. What is the average speed of the vehicle along the way?

1). Let the first half of the path S = L: 2, the car, moving uniformly at a speed of V1 = 22.2 m / s, has passed in time T1 = S: V1, that is, T1 = (L: 2): 22.2 (s).
2). Let the second half of the path S = L: 2, the car, moving unevenly with an average speed of V2 = 11.1 m / s, has passed in time T2 = S: V2, that is, T2 = (L: 2): 11.1 (s) …
3). To determine the average speed of the vehicle along the entire path, it is necessary to divide the entire path L traveled by the total time spent on it, that is, by T = (L: 2): 22.2 + (L: 2): 11.1 (s) : T = 15 • L: 222. Vav. = L: (15 • L: 222); Vav. = 14.8 m / s.
Answer: the average speed of the vehicle along the entire path Vav. = 14.8 m / s.

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