The first half of the time the helicopter moved north at a speed of 30 m / s, and the second half – to the east
The first half of the time the helicopter moved north at a speed of 30 m / s, and the second half – to the east at a speed of 40 m / s. a) Find the average ground speed of the helicopter b) Find the average speed of the helicopter
V1 = 30 m / s.
V2 = 40 m / s.
t1 = t2 = t / 2.
Vav1 -?
Vsrp2 -?
To find the average ground speed of movement Vav1, it is necessary to divide the entire path L traveled by the time of its movement t: Vav1 = L / t.
To find the average speed of the helicopter movement Vav2, it is necessary to divide its movement S by the time of its movement t: Vav2 = S / t.
L = L1 + L2.
L1 = V1 * t1 = V1 * t / 2.
L2 = V2 * t2 = V2 * t / 2.
L = V1 * t / 2 + V2 * t / 2 = (V1 + V2) * t / 2.
Vav1 = (V1 + V2) * t / 2 * t = (V1 + V2) / 2.
Vav1 = (30 m / s + 40 m / s) / 2 = 35 m / s.
Since the helicopter was moving in mutually perpendicular directions, S = √ (L1 ^ 2 + L2 ^ 2) = √ (V1 * t) ^ 2/4 + (V2 * t) ^ 2/4) = t * √ (V1 ^ 2 + V2 ^ 2) / 2.
Vav2 = t * √ (V1 ^ 2 + V2 ^ 2) / 2 * t = √ (V1 ^ 2 + V2 ^ 2) / 2.
Vav2 = √ (30 m / s) 2 + (40 m / s) 2) / 2 = 25 m / s.
Answer: Vav1 = 35 m / s, Vav2 = 25 m / s.