The first pipe passes 15 liters of water per minute less than the second. How many liters of water per minute does

The first pipe passes 15 liters of water per minute less than the second. How many liters of water per minute does the first pipe pass if it fills a tank with a volume of 100 liters 6 minutes faster than the second pipe?

To solve the problem, we will compose an equation in which the amount of water that the second pipe passes through is written as x.

In this case, the first pipe passes: x – 15 liters.

In this case, the time during which the first pipe fills a tank with a volume of 100 liters will be equal to:

100 / x – 15.

The time it takes for the second pipe to fill this tank will be:

100 / h.

The time difference will be 6 minutes.

We get:

(100 / (x – 15)) – (100 / x) = 6.

Letting go of the denominator.

100 * x – 100 * x + 1500 – 6 * x ^ 2 + 90 * x = 0.

-6 * x ^ 2 + 90 * x + 1500 = 0.

x ^ 2 – 15 * x – 250 = 0.

D = 1225.

x = (15 + 35) / 2 = 25 liters per minute.

Answer: For 25 l / min.