The first spring has a stiffness of 20 N / m, the second 40 N / m. The first one is stretched by 2 cm and the second by 1 cm.
| March 14, 2021 | education
The first spring has a stiffness of 20 N / m, the second 40 N / m. The first one is stretched by 2 cm and the second by 1 cm. Which is the ratio of the potential energy of the second spring to the potential energy of the first.
Problem data: k1 (stiffness of the first spring) = 20 N / m; k2 (stiffness of the second spring) = 40 N / m; Δx1 (deformation (tension) of the first spring) = 2 cm (0.02 m); Δx2 (deformation of the second spring) = 1 cm (0.01 m).
The ratio of potential energies of springs: n = En2 / En1 = 0.5 * k2 * Δx2 ^ 2 / (0.5 * k1 * Δx1 ^ 2) = k2 * Δx2 ^ 2 / (k1 * Δx1 ^ 2) = 40 * 0 , 01 ^ 2 / (20 * 0.02 ^ 2) = 1/2 = 0.5.
Answer: The ratio of the potential energy of the second spring to the potential energy of the first is 0.5.
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