The first third of the way the turtle crawled evenly in 1 hour, the second third – also evenly, but in 2 hours, the third

The first third of the way the turtle crawled evenly in 1 hour, the second third – also evenly, but in 2 hours, the third – the same way, but in three hours. How many times is the average speed in the first half of the journey more than in the second?

Since thirds of the path are given, all sections are equal to S1 = S2 = S3 = S
Let’s take the speed on the 1st section of the path for V. Then on the 2nd section of the path it covered this path, but in 2 hours, which means its speed was 2 times less = 0.5V, So the third part passed three times longer, V = 1 / 3V.
She traveled all the way in 3S. Halfway is equal to 1.5S.
The average speed is V = S / t. She passed the first S in 1 hour.
0.5 Second S she also passed in an hour, since she was moving evenly, 2 hours * 0.5 = 1 hour. V on 1 half of the way = 1.5 S / 2t. All the time 6 hours, the first half of the way is 2 hours, so the second half way 4 hours, so V = 1.5S / 4t
1.5S / 2t = 0.75V
1.5S / 4t = 0.375V
Let’s compare how many times 1 is more by dividing them.
0.75V / 0.375V = 2 times
Answer: The average speed on the 1st half of the journey was 2 times higher than on the 2nd half of the journey.