The first urn contains 7 red and 10 white balls. in the second 4 red and 8 white balls. from the first urn

The first urn contains 7 red and 10 white balls. in the second 4 red and 8 white balls. from the first urn the ball is transferred to the second, after which the ball is taken at random from the second urn. find the probability that it is red.

1) In order to solve this problem, we need to use the properties of the theory of probability.

2) There are two possible developments in total:

First:

3) A red ball is taken out of the first urn and put into the second urn and only 13 balls become in the second urn: 5 red and 8 white and the probability of falling out of red is calculated by dividing favorable events by the number of all events: 5/13 = 0, 38 …

Second:

4) A white ball is taken out of the first urn and put into the second urn and only 13 balls become in the second urn: 4 red and 9 white and the probability of falling out of red is calculated by dividing favorable events by the number of all events: 4/13 = 0.30 …

Answer: either 30% or 38%.