The first vessel with a volume of 2 × 10 ^ -3 m3 contains gas under a pressure of 1.7 × 10 ^ 5 Pa

| July 28, 2021 | education

The first vessel with a volume of 2 × 10 ^ -3 m3 contains gas under a pressure of 1.7 × 10 ^ 5 Pa, and in the second vessel with a volume of 3.2 × 10 ^ -3 m3 – gas under a pressure of 0.55 × 10 ^ 5 Pa at the same temperature. The vessels are interconnected by a thin tube with a tap. What pressure will be established in the vessels after the tap is opened? The temperature does not change.

To calculate the pressure value established in the vessels used, we apply the formula: P = Pk1 + Pk2 = Pn1 * V1 / (V1 + V2) + Pn2 * V2 / (V1 + V2) = (Pn1 * V1 + Pn2 * V2) / ( V1 + V2).

Variables: Рн1 – initial pressure of the first gas (Рн1 = 1.7 * 10 ^ 5 Pa); V1 is the volume of the first vessel (V1 = 2 * 10 ^ -3 m3); Рн2 – initial pressure of the second gas (Рн2 = 0.55 * 10 ^ 5 Pa); V2 is the volume of the second vessel (V2 = 3.2 * 10 ^ -3 m3).

Let’s calculate: P = (Pn1 * V1 + Pn2 * V2) / (V1 + V2) = (1.7 * 10 ^ 5 * 2 * 10 ^ -3 + 0.55 * 10 ^ 5 * 3.2 * 10 ^ -3) / (2 * 10 ^ -3 + 3.2 * 10 ^ -3) = 99.23 * 10 ^ 3 Pa = 99.23 kPa.

Answer: A pressure of 99.23 kPa will be established in the vessels used.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.