The flashlight bulb operates at a resistance of 120 m and a current of 2mA. find his tension.
| July 13, 2021 | education
R = 12 ohms.
I = 2 mA = 0.002 A.
U -?
According to Ohm’s law for a closed electric circuit, the current I is directly proportional to the voltage U and inversely proportional to the resistance R.
I = U / R.
U = I * R.
U = 0.002 A * 12 Ohm = 0.024 V.
Answer: the voltage in the flashlight bulb is U = 0.024 V.
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