The focal length of the diffusing lens is 3 cm. The object is located at a distance of 10 cm

The focal length of the diffusing lens is 3 cm. The object is located at a distance of 10 cm from the lens. What is the magnification of this optical system.

Let us replace in the formula of a thin diffusing lens: – 1 / F = 1 / d – 1 / f, where F is the focal length of the lens, d is the distance from the object to the lens, f is the distance from the image to the lens obtained with this lens, f by Г ∙ d, since the magnification of the optical system is Г = f / d. We get – 1 / F = 1 / d – 1 / (Г ∙ d), then Г = F / (d + F). It is known from the problem statement that the focal length of the scattering lens is F = 3 cm = 0.03 m, and the object is located at a distance d = 10 cm = 0.1 m from the lens. Substitute the values ​​of physical quantities in the formula and make calculations to find the magnification of this optical system: Г = 0.03 / (0.1 + 0.03); G = 3/13.
Answer: the optical system gives a magnification of 3/13.



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