The force of Archimedes acting on a cube immersed in water is 2N.

The force of Archimedes acting on a cube immersed in water is 2N. Determine the weight of a cube in air knowing that its weight in water is 0.5 N.

Farch = 2 N.
Pwater = 0.5 N.
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A body immersed in a liquid is acted upon by the force of gravity Ft vertically downward and the buoyant force of Archimedes vertically upward. Therefore, the body weight in water will be determined by the formula: Pwater = Ft – Farch.
In the air, the weight of the body will be equal to the force of gravity: Pair = Fт.
Pwater = Pair – Farch.
Air = Water + Far.
Pair = 0.5 N + 2 N = 2.5 N.
Answer: body weight in air Pair = 2.5 N.



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