The force of attraction between two equal 5 kg masses is 6.67 * 10 ^ -9 H What is the distance

The force of attraction between two equal 5 kg masses is 6.67 * 10 ^ -9 H What is the distance between the centers of the balls?

Given:

m1 = m2 = 5 kilograms – the mass of the balls;

F = 6.67 * 10 ^ -9 Newton – the force of attraction between the balls;

G = 6.67 * 10 ^ -11 N * m ^ 2 / kg ^ 2 – gravitational constant.

It is required to determine the distance between the balls R (meter).

According to the law of universal gravitation:

F = G * m1 * m2 / R ^ 2, hence:

R = (G * m1 * m2 / F) ^ 0.5 = (6.67 * 10 ^ -11 * 5 * 5 / (6.67 * 10 ^ -9) ^ 0.5 = (5 * 5 * 10 ^ -11 / 10 ^ -9) ^ 0.5 = (5 * 5 * 10 ^ -2) ^ 0.5 = (25 * 10 ^ -2) ^ 0.5 = 0.25 ^ 0.5 = 0.5 meters (50 centimeters).

Answer: The distance between two balls is 0.5 meters (50 centimeters).