The force of gravitational attraction between two bodies located at a distance of 2m is equal to 9N.

The force of gravitational attraction between two bodies located at a distance of 2m is equal to 9N. What will this force be equal to if the mass of one of the bodies is reduced by 2 times?

The force of gravitational attraction can be determined by the formula: F = G * m1 * m2 / R ^ 2, where G is the gravitational constant, m1 and m2 are the masses of bodies; R is the distance between bodies.

Initial state: 9H = F1 = G * m1 * m2 / R1 ^ 2 = G * m1 * m2 / 4.

The mass of one of the bodies was reduced by 2 times: F2 = G * 0.5 * m1 * m2 / R1 ^ 2 = 0.5 * G * m1 * m2 / 4 = G * m1 * m2 / 8.

F1 / F2 = 9 / F2 = (G * m1 * m2 / 4) / (G * m1 * m2 / 8) = 8/4 = 2/1 and F2 = 9/2 = 4.5 N.

Answer: The force of attraction will be 4.5 N.



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