The force of gravity that acts on the aluminum bar is 2646H. What is the volume of this bar?

These tasks: Ft (gravity acting on a taken aluminum bar) = 2646 N.

Reference values: g (acceleration due to gravity) ≈ 9.8 m / s2; ρа (density of aluminum) = 2700 kg / m3.

The volume of the taken aluminum bar is determined by the formula: V = m / ρа = Fт / (g * ρа).

Let’s calculate: V = 2646 / (9.8 * 2700) = 0.1 m3.

Answer: The volume of the taken aluminum bar is 0.1 m3.



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