The force with which the air presses on the surface of a table 2.4 m long and 50 cm wide is (take atmospheric pressure 10 ^ 5 Pa)

Initial data: a (table length) = 2.4 m; b (table width) = 50 cm = 0.5 m; P (atmospheric pressure) = 10 ^ 5 Pa.

1) Determine the surface area of the table (rectangle area): S = a * b = 2.4 * 0.5 = 1.2 m ^ 2.

2) Let’s calculate the force with which the air presses on the table surface: P = F / S and F = P * S = 10 ^ 5 * 1.2 = 120 kN.

Answer: Air presses on the table top with a force of 120 kN.