The forces of 4 N and 20 N act on the ends of the lever. The length of the lever is 1.5 m. Where is the fulcrum

The forces of 4 N and 20 N act on the ends of the lever. The length of the lever is 1.5 m. Where is the fulcrum if the lever is in equilibrium?

Let the distance of the first force be equal to x, then for the other force – the shoulder is equal to 1.5 – x.
Based on the condition of the balance of the lever, we have: 4/20 = 1.5 – x / x.
We solve the equation: 4 * x = 20 * (1.5 – x);
4 * x = 30 – 20 * x;
4 * x + 20 * x = 30;
24 * x = 30;
x = 30/24;
x = 1.25.
Result: There is a support point 1.25 m from the point of lesser force and 0.25 m (1.5 m – 1.25 m) from the point of application of the greater force.