The forces of electrostatic interaction between two point charged bodies is equal in modulus F.

The forces of electrostatic interaction between two point charged bodies is equal in modulus F. How will the modulus of forces of electrostatic interaction between these bodies change if the distance between them is increased by 2 times?

Let us write down the force expression for the initial state of the bodies

F1 = k * | q1 | * | q2 | / r1².

Strength after increasing distance

F2 = k * | q1 | * | q2 | / r2².

Let’s find how many times the strength has changed

D = F1 / F2 = (k * | q1 | * | q2 | / r1²) / (k * | q1 | * | q2 | / r2²) = r2² / r1².

The distance has doubled, which means

r2 = 2 * r1.

Then

D = (2 * r1) ² / r1² = 4.

Answer: the modulus of the forces of electrostatic interaction between these bodies will change 4 times.